document.write( "Question 12162: I need help! problem is 3/4t-5/4=1/3t \n" ); document.write( "
Algebra.Com's Answer #6174 by elima(1433) ![]() You can put this solution on YOUR website! 3/4t-5/4=1/3t\r \n" ); document.write( "\n" ); document.write( "We begin by getting the \"t\" on one side and the 5/4 on the other.\r \n" ); document.write( "\n" ); document.write( "So we subtract add 5/4 on both sides: \n" ); document.write( "3/4t-5/4+5/4=1/3t+5/4 \n" ); document.write( "That cancels out the 5/4 on the right and leaves: \n" ); document.write( "3/4t=1/3t+5/4 \n" ); document.write( "Now we will subtract the 1/3t from both sides, \n" ); document.write( "3/4t-1/3t=1/3t+5/4-1/3t \n" ); document.write( "Now we have the \"t's\" on one side and 5/4 on the other. \n" ); document.write( "When add or subtract fractions we have to get the LCD. so to add 3/4+1/3 we need the LCD. Which is 12. \n" ); document.write( "So now we have: \n" ); document.write( "9/12t-4/12t=5/4 \n" ); document.write( "5/12t=5/4 \n" ); document.write( "To get rid of the 5/12 on the left side, so you can have t alone. You need to add it inverse, which is 12/5.And remember what you do to one side you do to the other. \n" ); document.write( "5/12t(12/5)=5/4(12/5) \n" ); document.write( "That leaves us with: \n" ); document.write( "t=60/20 \n" ); document.write( "t=3 \n" ); document.write( "DONE!!!(YAH) \n" ); document.write( "Hope you understand! =) \n" ); document.write( " |