document.write( "Question 999670: One number is 9 times a first number. A third is 100 more than the first number. If the sum of the three numbers is 518, find the numbers. \n" ); document.write( "
Algebra.Com's Answer #617357 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "F=first number; S=second number=9F; T=third number=F+100 \n" ); document.write( ". \n" ); document.write( "F+S+T=518 \n" ); document.write( "F+9F+F+100=518 \n" ); document.write( "11F=418 \n" ); document.write( "F=38 \n" ); document.write( "S=9F=342 \n" ); document.write( "T=F+100=38+100=138 \n" ); document.write( ". \n" ); document.write( "ANSWER: The numbers are 38, 342, and 138. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "F+S+T=518 \n" ); document.write( "38+342+138=518 \n" ); document.write( "518=518 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |