document.write( "Question 999670: One number is 9 times a first number. A third is 100 more than the first number. If the sum of the three numbers is 518, find the numbers. \n" ); document.write( "
Algebra.Com's Answer #617357 by macston(5194)\"\" \"About 
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\n" ); document.write( "F=first number; S=second number=9F; T=third number=F+100
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\n" ); document.write( "F+S+T=518
\n" ); document.write( "F+9F+F+100=518
\n" ); document.write( "11F=418
\n" ); document.write( "F=38
\n" ); document.write( "S=9F=342
\n" ); document.write( "T=F+100=38+100=138
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\n" ); document.write( "ANSWER: The numbers are 38, 342, and 138.
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\n" ); document.write( "CHECK:
\n" ); document.write( "F+S+T=518
\n" ); document.write( "38+342+138=518
\n" ); document.write( "518=518
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