document.write( "Question 999791: 16x^2(x+4) can be written as a product of 8(x+4) and what term?
\n" ); document.write( "A)2x^2(x+4)
\n" ); document.write( "B)16x(x+4)
\n" ); document.write( "C)128x^2(x+4)^2
\n" ); document.write( "D)2x^2
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Algebra.Com's Answer #617334 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "compare \"16x%5E2%28x%2B4%29\" and \"8%28x%2B4%29\": \r
\n" ); document.write( "\n" ); document.write( "in \"16x%5E2%28x%2B4%29\" first term is \"16x%5E2\" and second term is \"%28x%2B4%29\"\r
\n" ); document.write( "\n" ); document.write( "in \"8%28x%2B4%29\" first term is \"8\" and second term is \"%28x%2B4%29\"\r
\n" ); document.write( "\n" ); document.write( "since second terms are equal, make first terms equal too\r
\n" ); document.write( "\n" ); document.write( "\"16x%5E2\" will be equal to \"8\" only if we multiply it by \"2x%5E2\":\"8%2A2x%5E2=16x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "then, \"16x%5E2%28x%2B4%29\" can be written as a product of \"8%28x%2B4%29\" and \"2x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"16x%5E2%28x%2B4%29=8%28x%2B4%29%282x%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "so, answer is:\r
\n" ); document.write( "\n" ); document.write( "D)\"2x%5E2\"\r
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