document.write( "Question 999782: Grace drove a distance of 189 miles. Part of the time she averaged 65mph and for the remaining time, she averaged 55mph. The entire trip took 3 hours? How long did she travel at each rate? \n" ); document.write( "
Algebra.Com's Answer #617326 by macston(5194)\"\" \"About 
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\n" ); document.write( "M=miles at 65 mph; 189-M=miles at 55 mph
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\n" ); document.write( "(M/65)+(189-M)/55=3 hours
\n" ); document.write( "(55M/3575)+(65(189-M)/3575)=3 hours
\n" ); document.write( "(55M+12285-65M)/3575=3 hours
\n" ); document.write( "-10M+12285=10725
\n" ); document.write( "-10M=--1560
\n" ); document.write( "M=156
\n" ); document.write( "She drove 156 miles at 65 mph.
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\n" ); document.write( "156 mi/65 mph=2.4 hours
\n" ); document.write( "ANSWER 1: She drove 2.4 hours at 65 mph
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\n" ); document.write( "189-M = 189-156 = 33miles
\n" ); document.write( "She drove 33 miles at 55 mph
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\n" ); document.write( "33 mi/55 mph=0.6 hours
\n" ); document.write( "ANSWER 2: She drove 0.6 hours at 55 mph.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "(Time at 65 mph)(65 mph)+ (Time at 55 mph)(55 mph)=189 mi
\n" ); document.write( "(2.4 hrs)(65 mph)+(0.06 hrs)(55 mph)=189 mi
\n" ); document.write( "156 mi + 33 mi = 189 mi
\n" ); document.write( "189 mi = 189 mi
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