document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85505>Question 85505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve algebraically? y=5x+6 and 2x-5y=16. I cannot figure this one out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61731 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve algebraically? y=5x+6 and 2x-5y=16.<BR>\n" );
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document.write( "You need to assume the \"y\" in the two equations mean the same number.<BR>\n" );
document.write( "Then you substitute the value of y (y=5x+6) into the other equation<BR>\n" );
document.write( "so you can solve for \"x\".<BR>\n" );
document.write( "You get: 2x-5(5x+6)=16<BR>\n" );
document.write( "2x-25x-30=16<BR>\n" );
document.write( "-23x = 46<BR>\n" );
document.write( "x=-2<BR>\n" );
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document.write( "Then you substitute that value of x into \"y=5x+6\" so you can solve<BR>\n" );
document.write( "for \"y\".<BR>\n" );
document.write( "y=5*-2+6<BR>\n" );
document.write( "y=-10+6<BR>\n" );
document.write( "y=-4<BR>\n" );
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document.write( "So the solution is x=-2, y=-4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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