document.write( "Question 85500: Please help me with this problem as I am terrible at math. It comes from a worksheet.
\n" ); document.write( "John drove to his uncle’s house in a distant city and the trip took 5 hours. When he returned home, there was less traffic and the trip only took 3 hours. If John drove 26 miles per hour faster on the return trip, how fast did he drive each way?\r
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Algebra.Com's Answer #61730 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
John drove to his uncle’s house in a distant city and the trip took 5 hours. When he returned home, there was less traffic and the trip only took 3 hours. If John drove 26 miles per hour faster on the return trip, how fast did he drive each way?
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\n" ); document.write( "Let s = speed to
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\n" ); document.write( "(s+26) = speed back
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\n" ); document.write( "We know the distance there and back is the same so we can make a simple equation from that fact:
\n" ); document.write( "Distance = time * speed:
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\n" ); document.write( "To dist = back dist
\n" ); document.write( "5*s = 3(s+26)
\n" ); document.write( "5s = 3s + 78
\n" ); document.write( "5s - 3s = 78
\n" ); document.write( "2s = 78
\n" ); document.write( "s = 78/2
\n" ); document.write( "s = 39 mph to, and 39+26 = 65 mph on the return trip
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\n" ); document.write( "A good way to check our solution is find the distances, they should be equal:
\n" ); document.write( "5 * 39 = 195
\n" ); document.write( "3 * 65 = 195 also, proves our solutions
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\n" ); document.write( "That's not so hard, is it? Did it make sense to you?
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