document.write( "Question 999742: Determine the cubic equation that has zeros at 4,3 and -2, if f(2)=-4.
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document.write( "Work I have done so far:
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document.write( "x-4=0, x-3=0, x+2=0
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document.write( "(x-4)(x-3)(x+2)=0\r
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document.write( "Help would be greatly appreciated, thanks! :) \n" );
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Algebra.Com's Answer #617292 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Determine the cubic equation that has zeros at 4,3 and -2, if f(2)=-4. \n" ); document.write( "Work I have done so far: \n" ); document.write( "Factors:: x-4, x-3, x+2 \n" ); document.write( "Equation: y = a(x-4)(x-3)(x+2) \n" ); document.write( "-------- \n" ); document.write( "Solve for \"a\" using (2,-4) \n" ); document.write( "-4 = a(-2)(-1)(4) \n" ); document.write( "a = -4/8 \n" ); document.write( "a = -1/2 \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "y = (-1/2)(x-4)(x_3)(x+2) \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |