document.write( "Question 85506: Four years ago, the sum of the ages of A & B was 45. Six years from now, twice B's age will be 28 years more than A's age then. How old is A now? \n" ); document.write( "
Algebra.Com's Answer #61729 by Nate(3500)\"\" \"About 
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Four years ago, the sum of the ages of A & B was 45.
\n" ); document.write( "A - 4 and B - 4 = 45
\n" ); document.write( "A + B - 8 = 45
\n" ); document.write( "A + B = 53
\n" ); document.write( "Six years from now, twice B's age will be 28 years more than A's age then. How old is A now?
\n" ); document.write( "2(B + 6) = 28 + (A + 6)
\n" ); document.write( "2B + 12 = 34 + A
\n" ); document.write( "2B - 22 = A
\n" ); document.write( "Plug:
\n" ); document.write( "A + B = 53
\n" ); document.write( "2B - 22 + B = 53
\n" ); document.write( "3B = 75
\n" ); document.write( "B = 25
\n" ); document.write( "Plug:
\n" ); document.write( "A + B = 53
\n" ); document.write( "A + 25 = 53
\n" ); document.write( "A = 28
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