document.write( "Question 999717: Find a cubic polynomial in standard form with real coefficients, having the zeros 2 and 6i. Let the leading coefficient be 1 \n" ); document.write( "
Algebra.Com's Answer #617268 by ikleyn(52817)\"\" \"About 
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\n" ); document.write( "Find a cubic polynomial in standard form with real coefficients, having the zeros 2 and 6i. Let the leading coefficient be 1
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\n" ); document.write( "\n" ); document.write( "(x-2)*(x-6i)*(x-(-6i)) = \"%28x-2%29%2A%28x%5E2+%2B+36%29\".\r
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\n" ); document.write( "\n" ); document.write( "1.  If a polynomial with real coefficients has a complex root,  it has the conjugate complex number as a root,  too.\r
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\n" ); document.write( "\n" ); document.write( "2.  If a polynomial  f(x)  of a degree  n  with leading coefficient  1  has  n  roots  \"x%5B1%5D\", \"x%5B2%5D\", . . . , \"x%5Bn%5D\"  then the polynomial is the product \r
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\n" ); document.write( "\n" ); document.write( "      f(x) = \"%28x-x%5B1%5D%29%2A%28x-x%5B2%5D%29%2A+ellipsis+%2A+%28x-x%5Bn%5D%29\".\r
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