document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999607>Question 999607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ``solve each system of equations by the substitution method\r<BR>\n" );
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document.write( "X=(5/6)y-2<BR>\n" );
document.write( "12x-5y=-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617203 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We substitute the x from the first equation into the second and get<BR>\n" );
document.write( "x=(5/6)y-2<BR>\n" );
document.write( "12x-5y=-9<BR>\n" );
document.write( "and<BR>\n" );
document.write( "12[(5/6)y - 2] - 5y = -9<BR>\n" );
document.write( "10y - 24 - 5y = -9<BR>\n" );
document.write( "5y - 24 = -9<BR>\n" );
document.write( "5y = 15<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "x = (5/6)(3) - 2<BR>\n" );
document.write( "x = (5/2) - 2<BR>\n" );
document.write( "x = 1/2 </SPAN>\n" );
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