document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85496>Question 85496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate b to the power of 2-2bc+c to the power of 2. If b=3 and c=-2.\r<BR>\n" );
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document.write( "Solve 10x-4-5x=6+3x-8\r<BR>\n" );
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document.write( "Thanks\r<BR>\n" );
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document.write( "(two different problems) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61720 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Problem 1: b to the power of 2-2bc+c to the power of 2. If b=3 and c=-2.<BR>\n" );
document.write( "2-2bc+c=2-(-12)-2=14-2=12<BR>\n" );
document.write( "power2=24<BR>\n" );
document.write( "3 power 12 power 2<BR>\n" );
document.write( "=3^24<BR>\n" );
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document.write( "Problem 2<BR>\n" );
document.write( "10x-4-5x=6+3x-8<BR>\n" );
document.write( "10x-5x-3x=6+4+8<BR>\n" );
document.write( "2x=2<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "ok\r<BR>\n" );
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