document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999611>Question 999611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ``solve each system of equations by the substitution method\r<BR>\n" );
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document.write( "6x-3y=5<BR>\n" );
document.write( "X+2y=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617192 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the second one and substitute into the first equation...<BR>\n" );
document.write( "6x-3y=5<BR>\n" );
document.write( "x+2y=0<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = -2y<BR>\n" );
document.write( "and<BR>\n" );
document.write( "6(-2y)-3y=5<BR>\n" );
document.write( "-12y-3y=5<BR>\n" );
document.write( "-15y=5<BR>\n" );
document.write( "divide by -15 and get<BR>\n" );
document.write( "y = -1/3<BR>\n" );
document.write( "x = 2(-1/3) = 2/3 </SPAN>\n" );
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