document.write( "Question 999539: It says to solve each system by substitution and elimination but I don't understand on how to do it.
\n" ); document.write( "Y=-3x+4
\n" ); document.write( "Y=3x-2
\n" ); document.write( "

Algebra.Com's Answer #617157 by MathTherapy(10552)\"\" \"About 
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It says to solve each system by substitution and elimination but I don't understand on how to do it.
\n" ); document.write( "Y=-3x+4
\n" ); document.write( "Y=3x-2
\n" ); document.write( "
ELIMINATION
\n" ); document.write( "y = - 3x + 4 --- eq (i)
\n" ); document.write( "y = 3x - 2 ----- eq (ii)
\n" ); document.write( "2y = 2 --------- Adding eqs (ii) & (i)
\n" ); document.write( "y = \"2%2F2\", or \"highlight_green%281%29\"
\n" ); document.write( "1 = - 3x + 4 ------- Substituting 1 for y in eq (i)
\n" ); document.write( "3x = 4 - 1
\n" ); document.write( "3x = 3
\n" ); document.write( "x = \"3%2F3\", or \"highlight_green%28x+=+1%29\"
\n" ); document.write( "SUBSTITUTION
\n" ); document.write( "Since both equations have already been solved for y, then just set them equal to each other, as follows: - 3x + 4 = 3x - 2
\n" ); document.write( "Solve this for x, then find y \n" ); document.write( "
\n" );