document.write( "Question 999537: Adam is 10 years younger than Barry and Charles is 10 years older than Barry. If Charles is
\n" ); document.write( "three times older than Adam, find each boy's age.\r
\n" ); document.write( "\n" ); document.write( "if you could help me set up the problem I am sure to figure it out. this is what i have so far.\r
\n" ); document.write( "\n" ); document.write( "b-10=a
\n" ); document.write( "c+10=b
\n" ); document.write( "3a=c\r
\n" ); document.write( "\n" ); document.write( "Is that set up right?
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Algebra.Com's Answer #617145 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Everything you have done is technically correct, but you are probably going to confuse the hell out of yourself using three variables -- certainly confuses me.\r
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\n" ); document.write( "\n" ); document.write( "Try it this way:\r
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\n" ); document.write( "\n" ); document.write( "Let represent Adam's age. Then Barry's age is , and Charles' age is .\r
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\n" ); document.write( "\n" ); document.write( "Now you can say:\r
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\n" ); document.write( "\n" ); document.write( "and solve for \r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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