document.write( "Question 999537: Adam is 10 years younger than Barry and Charles is 10 years older than Barry. If Charles is
\n" ); document.write( "three times older than Adam, find each boy's age.\r
\n" ); document.write( "\n" ); document.write( "if you could help me set up the problem I am sure to figure it out. this is what i have so far.\r
\n" ); document.write( "\n" ); document.write( "b-10=a
\n" ); document.write( "c+10=b
\n" ); document.write( "3a=c\r
\n" ); document.write( "\n" ); document.write( "Is that set up right?
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Algebra.Com's Answer #617144 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
This is the system, translated exactly according to the description:
\n" ); document.write( "\"system%28a=-10%2Bb%2Cc=10%2Bb%2Cc=3a%29\"\r
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\n" ); document.write( "\n" ); document.write( "A simple rearrangement can be \"system%28a=b-10%2Cc=b%2B10%2Cc=3a%29\". Various ways to solve the system for a, b, c.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28a=b-10%2Cb%2B10=3a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28a=b-10%2Cb=3a-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"a=%283a-10%29-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"a=3a-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2a=-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28a=10%29\"-------one of the values solved.
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