document.write( "Question 999527: A rectangular parcel of land has an area of 5,000 ft^2. A diagonal between opposite corners is measured to be 20 ft longer than one side of the parcel. What are the dimensions of the land, correct to the nearest foot? \n" ); document.write( "

Algebra.Com's Answer #617141 by mananth(16946) $\"\"$ $\"About$

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let one side be x\r
\n" ); document.write( "\n" ); document.write( "Area = 5000\r
\n" ); document.write( "\n" ); document.write( "so other side is 5000/x\r
\n" ); document.write( "\n" ); document.write( "diagonal is (x+20)\r
\n" ); document.write( "\n" ); document.write( "using Pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( " $\"%28x%2B20%29%5E2+=+x%5E2%2B%285000%2Fx%29%5E2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B40x%2B400+=+x%5E2+%2B+25000000%2Fx%5E2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"40x%2B400+-25000000%2Fx%5E2+=0\"$ \r
\n" ); document.write( "\n" ); document.write( "/40\r
\n" ); document.write( "\n" ); document.write( "x+10 -625000/x^2=0\r
\n" ); document.write( "\n" ); document.write( "x^3+10x^2-625000=0\r
\n" ); document.write( "\n" ); document.write( "solve cubic equation\r
\n" ); document.write( "\n" ); document.write( "x=82.3\r
\n" ); document.write( "\n" ); document.write( "dimensions are 82.3 & 60.7 ft\r
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