document.write( "Question 999517: solve each system of equations by the substitution method
\n" ); document.write( "3y-x=6
\n" ); document.write( "4x+12y=0
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Algebra.Com's Answer #617135 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "-1 x + 3 y = 6 .............1
\n" ); document.write( "3 y = 6 + 1 x
\n" ); document.write( "/ 3 =
\n" ); document.write( " y = 2 + 1/3 x
\n" ); document.write( "4 x + 12 y = 0 .....................2
\n" ); document.write( "Substitute y in (2)
\n" ); document.write( "4 x + 12 ( 2 + 1/3 x ) = 0
\n" ); document.write( "4 x + 24 + 4 x = 0
\n" ); document.write( "4 x 4 x = -24
\n" ); document.write( "8 x = -24
\n" ); document.write( "/ 8
\n" ); document.write( "x= -3
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "-1 x + 3 y = 6
\n" ); document.write( "-1 * -3 + 3 y = 6
\n" ); document.write( "3 + 3 y = 6
\n" ); document.write( "3 y = 3
\n" ); document.write( "/ 3
\n" ); document.write( "y= 1
\n" ); document.write( "m.ananth@hotmail.ca
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