document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999502>Question 999502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance it takes to stop a car varies directly as the square of the speed of the car. If it takes 112 feet for a car traveling at 40 miles per hour to stop, what distance is required for a speed of 55 miles per hour?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617116 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The distance it takes to stop a car varies directly as the square of the speed of the car. If it takes 112 feet for a car traveling at 40 miles per hour to stop, what distance is required for a speed of 55 miles per hour? <BR>\n" );
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document.write( "d = k*s^2<BR>\n" );
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document.write( "112 = k*40^2<BR>\n" );
document.write( "k = 112/1600 = 0.07<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "d = 0.07*s^2<BR>\n" );
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document.write( "What distance is required for a speed of 55 miles per hour?<BR>\n" );
document.write( "d = 0.7*55^2 = 211.75 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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