document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999330>Question 999330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Derivation of T &#8733; &#8730;l\r<BR>\n" );
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document.write( "Derivation of T = 2&#960;&#8730;(l/g)\r<BR>\n" );
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document.write( "T = Time Period of a pendulum<BR>\n" );
document.write( "l = length of the pendulum<BR>\n" );
document.write( "g = gravity </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617062 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The relationship between the pendulum's period T and the square root of the length of the string has a constant of proportionality equal to<BR>\n" );
document.write( "2(pi)/sqrt(g)<BR>\n" );
document.write( "The derivation of the overall formula is quite complicated...this formula is really an approximation that is only valid for small angles theta... </SPAN>\n" );
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