document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999348>Question 999348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using laws of logarithms, write the expression below as a single logarithm.<BR>\n" );
document.write( "(1/3)log125-(1/2)log64 = (???????????????)<BR>\n" );
document.write( "Please help!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617029 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/3)log125-(1/2)log64 =<BR>\n" );
document.write( "(1/3)log(5^3)-(1/2)log(2^6)=<BR>\n" );
document.write( "(1/3)3log(5)-(1/2)6log(2)=<BR>\n" );
document.write( "log 5 - 3 log 2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );