document.write( "Question 999326: Find the equation of the hyperbola having foci at(4,2)and (8,2) and eccentricity (e) is 2 \n" ); document.write( "
Algebra.Com's Answer #617008 by MathLover1(20850)\"\" \"About 
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the equation is:\r
\n" ); document.write( "\n" ); document.write( " \"%28x+-+h%29%5E2+%2F+a%5E2+-+%28y+-+k%29%5E2+%2F+b%5E2=+1\"\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( " foci at(\"4\",\"2\") and (\"8\",\"2\") and
\n" ); document.write( " eccentricity \"e=+2\"\r
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\n" ); document.write( "\n" ); document.write( "The center is midway between the foci, so the center must be at (\"h\", \"k\") = (\"6\", \"2\"). The foci are \"2+\" units to either side of the center, so \"c+=+2\" and \"c%5E2+=+4\". \r
\n" ); document.write( "\n" ); document.write( "since \"e=+c%2Fa\", we have \"2=+2%2Fa\"=>\"a=2%2F2\"=>\"a=1\"\r
\n" ); document.write( "\n" ); document.write( "since \"c+=+2\" and \"a=1\", then
\n" ); document.write( "\"+b%5E2+=+c%5E2-a%5E2+\"
\n" ); document.write( "\"+b%5E2+=+4-1+\"
\n" ); document.write( "\"+b%5E2+=+3+\"
\n" ); document.write( "\"+b+=+sqrt%283%29+\"\r
\n" ); document.write( "\n" ); document.write( "your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+6%29%5E2%2F1+-+%28y+-+2%29%5E2%2F3=+1\"\r
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