document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999211>Question 999211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the formula f(n) = 3(-1)n find the first 5 terms of this sequence </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616987 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From f(n) = 3(-1)n, we look at f(1) thru f(5) and get<BR>\n" );
document.write( "f(1) = -3<BR>\n" );
document.write( "f(2) = -6<BR>\n" );
document.write( "f(3) = -9<BR>\n" );
document.write( "f(4) = -12<BR>\n" );
document.write( "f(5) = -15<BR>\n" );
document.write( "If you meant f(n) = 3(-1)^n, then there are different answers...<BR>\n" );
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