document.write( "Question 999302: Five years ago a mother was twice as old as her son in six years time the sum of their ages will be 82. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #616979 by stanbon(75887)\"\" \"About 
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Five years ago a mother was twice as old as her son.
\n" ); document.write( "In six years time the sum of their ages will be 82.
\n" ); document.write( "Find their present ages.
\n" ); document.write( "--------
\n" ); document.write( "Equations:
\n" ); document.write( "m-5 = 2(s-5)
\n" ); document.write( "m+6 + s+6 = 82
\n" ); document.write( "------
\n" ); document.write( "Rearrange::
\n" ); document.write( "m - 2s = -5
\n" ); document.write( "m + s = 70
\n" ); document.write( "--------------------
\n" ); document.write( "Subtract and solve for \"s\":
\n" ); document.write( "3s = 75
\n" ); document.write( "son's age = 25 yrs
\n" ); document.write( "-----------
\n" ); document.write( "Solve for \"m\":
\n" ); document.write( "m + s = 70
\n" ); document.write( "mother's age = 55 yrs
\n" ); document.write( "---------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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