document.write( "Question 999302: Five years ago a mother was twice as old as her son in six years time the sum of their ages will be 82. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #616979 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Five years ago a mother was twice as old as her son. \n" ); document.write( "In six years time the sum of their ages will be 82. \n" ); document.write( "Find their present ages. \n" ); document.write( "-------- \n" ); document.write( "Equations: \n" ); document.write( "m-5 = 2(s-5) \n" ); document.write( "m+6 + s+6 = 82 \n" ); document.write( "------ \n" ); document.write( "Rearrange:: \n" ); document.write( "m - 2s = -5 \n" ); document.write( "m + s = 70 \n" ); document.write( "-------------------- \n" ); document.write( "Subtract and solve for \"s\": \n" ); document.write( "3s = 75 \n" ); document.write( "son's age = 25 yrs \n" ); document.write( "----------- \n" ); document.write( "Solve for \"m\": \n" ); document.write( "m + s = 70 \n" ); document.write( "mother's age = 55 yrs \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |