document.write( "Question 999197: The arch under the kemp channel bridge is in the shape of a parabola lake archway. The arch is modeled by the equation h(x)=16x-x^2, where h(x) is the distance, in feet, the archer is above the water from the value of x.
\n" ); document.write( "A. For what value of X will the Archway be 28 feet above the water?
\n" ); document.write( "B. How wide is the Archway At the water?
\n" ); document.write( "C. What is the maximum height of the arch?
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Algebra.Com's Answer #616969 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "h(x) = 16x - x^2.
\n" ); document.write( "A) For what value of X will the Archway be 28 feet above the water?
\n" ); document.write( "28 = 16x - x^2
\n" ); document.write( "Multiply through by -1
\n" ); document.write( "x^2 - 16x + 28 = 0
\n" ); document.write( "(x - 2)(x - 14) = 0
\n" ); document.write( "x = 2 and x = 14
\n" ); document.write( "B) How wide is the Archway At the water?
\n" ); document.write( "16x - x^2 = 0
\n" ); document.write( "x(16 - x) = 0
\n" ); document.write( "x = 0 and x = 16
\n" ); document.write( "Width = 16 ft
\n" ); document.write( "C)What is the maximum height of the arch?
\n" ); document.write( "Mid point x = 8
\n" ); document.write( "h(x) = 16(8) - 8^2
\n" ); document.write( "h(x) = 128 - 64
\n" ); document.write( "Height = 64 ft.
\n" ); document.write( "Hope this helps :-)
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