document.write( "Question 999158: Joel took two exams. He scored 14 points less on the second test than he did on the first. His average score for the two exams was 84 points. If x= his score on the first test, and y= his score on the second tests, then the average is given by the formula x+y/2. What did joel score on the second test? \n" ); document.write( "
Algebra.Com's Answer #616952 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
average score is (x+y)/2
\n" ); document.write( "he scored 14 points less on the second test than he did on the first.
\n" ); document.write( "y = x - 14.
\n" ); document.write( "replace y with x-14 to get the average score to be equal to (x + x - 14) / 2 which results in (2x-14)/2
\n" ); document.write( "since the average score on both tests is 84, then you get:
\n" ); document.write( "(2x-14)/2 = 84
\n" ); document.write( "multiply both sides of this equation by 2 to get:
\n" ); document.write( "2x-14 = 168
\n" ); document.write( "add 14 to both sides of this equation to get:
\n" ); document.write( "2x = 182
\n" ); document.write( "divide both sides of this equation by 2 to get:
\n" ); document.write( "x = 91
\n" ); document.write( "he got 91 on the first test.
\n" ); document.write( "he got 91 - 14 = 77 on the second test.
\n" ); document.write( "(91 + 77) / 2 = 168/2 = 84 average on both tests.
\n" ); document.write( "he scored 77 on the second test is your solution.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );