document.write( "Question 999272: Bob takes 3 hours to mow a lawn. Al takes 4 hours. If they work together how long will it take\r
\n" ); document.write( "\n" ); document.write( "In the previous problem Al works for 1.5 hours BEFORE Bob arrives, how much longer will it
\n" ); document.write( "take if they finish together?\r
\n" ); document.write( "\n" ); document.write( "The answer for the first problem is 12/7 hrs. I'd like to know how to work out the second please!
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Algebra.Com's Answer #616940 by josgarithmetic(39627)\"\" \"About 
You can put this solution on YOUR website!
The current problem works this way:
\n" ); document.write( "Bob's rate, \"1%2F3\".
\n" ); document.write( "Al's rate, \"1%2F4\".
\n" ); document.write( "Both together, \"1%2F3%2B1%2F4=4%2F12%2B3%2F12=highlight%287%2F12%29\". The unit is LAWNS per HOUR.
\n" ); document.write( "....Yes, you can look at that rate upside down to figure how much TIME for one job and this is \"12%2F7\" HOURS per job. Twelve hours for seven jobs or, \"1%265%2F7\" hours for one job or however you want to express it.\r
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\n" ); document.write( "\n" ); document.write( "The \"previous\" problem works this way:
\n" ); document.write( "Al works \"1%261%2F2\" hours, and does some work; and then Al and Bob work together for some unknown \"t\" hours and they finish the 1 job.
\n" ); document.write( "-
\n" ); document.write( "\"highlight_green%28%281%2F4%29%283%2F2%29%2B%287%2F12%29%2At=1%29\".
\n" ); document.write( "Solve this for t.
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