document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999261>Question 999261</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A line passes through the points -2 and -7 and has a slope of 3 write an equation for this line </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616924 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">    <BR>\n" );
document.write( "the general form of equation is\r<BR>\n" );
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document.write( "(y-y1) = m(x-x1)\r<BR>\n" );
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document.write( "m = slope<BR>\n" );
document.write( "and (x1,y1) are the co ordinates of a point on the line\r<BR>\n" );
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document.write( "(y-(-7)) = 3(x-(-2))\r<BR>\n" );
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document.write( "y+7= 3x+6\r<BR>\n" );
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document.write( "3x-y=1 </SPAN>\n" );
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