document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999250>Question 999250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 220 meters. The length is 10 meters greater than the width. Find the dimensions of the rectangle. <BR>\n" );
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document.write( " length   m <BR>\n" );
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document.write( "  width   m <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616922 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L= W+10 Let's use this value for Length in the formula below:<BR>\n" );
document.write( "2L+2W= perimeter<BR>\n" );
document.write( "2(W+10)+2W= 220 Multiply:<BR>\n" );
document.write( "2W+20+2W= 220 Subtract 20 on both sides and add W on left:<BR>\n" );
document.write( "4W= 200 Divide both sides by 4:<BR>\n" );
document.write( "W= 50 This is the width, and the length is 10 more:<BR>\n" );
document.write( "L= 50+10= 60<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2(50)+2(60)= 220<BR>\n" );
document.write( "100+ 120= 220<BR>\n" );
document.write( "220 = 220 We have the correct answer<BR>\n" );
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