document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999207>Question 999207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A powerboat takes 30 minutes to travel 10 miles downstream.  The return trip takes 50 minutes.  What is the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616887 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A powerboat takes 30 minutes to travel 10 miles downstream. The return trip takes 50 minutes. What is the speed of the current? <BR>\n" );
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document.write( "Downstream DATA:<BR>\n" );
document.write( "time = (1/2) hr ; distance = 10 miles ; rate = d/r = 20 mph<BR>\n" );
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document.write( "Upstream DATA:<BR>\n" );
document.write( "time = (5/6) hr ; distance = 10 miles ; rate = 10/(5/6) = 12 mph<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "b + c = 20 mph<BR>\n" );
document.write( "b - c = 12 mph<BR>\n" );
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document.write( "2b = 32<BR>\n" );
document.write( "b = 16 (Speed of the boat in still water)<BR>\n" );
document.write( "c = 4 mph (speed of the current)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );