document.write( "Question 999194: simplify (6+3i)(2i-4)-(4i+5i) \n" ); document.write( "
Algebra.Com's Answer #616871 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "simplify (6+3i)(2i-4)-(4i+5i)
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\n" ); document.write( "\n" ); document.write( "(6 + 3i)*(2i - 4) - (4i + 5i) = 6*(2i) - 24 + (3i)*(2i) -4*(3i) - (9i) = 12i - 24 + 6i^2 - 12i - 9i = -24 - 6 - 9i = -30 - 9i.\r
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\n" ); document.write( "\n" ); document.write( "You make all calculations as if  i  is a regular symbol.
\n" ); document.write( "Remember that \"i%5E2\" = -1,  and every time you have  \"i%5E2\", replace it by  (-1).\r
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