document.write( "Question 999132: There are 100 candy bars. Some cost 75 cents; some cost $1. The total cost was $80. How
\n" ); document.write( "many $1 bars? \n" ); document.write( "
Algebra.Com's Answer #616868 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "Answer.  80*$0.75 + 20*$1 = $60 + $20 = 80 dollars.\r
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\n" ); document.write( "\n" ); document.write( "Let us assume for a minute that all the bars are priced $1 each. \r
\n" ); document.write( "\n" ); document.write( "Then the total cost would be  $100,  in  $20 more than  $80.\r
\n" ); document.write( "\n" ); document.write( "It is clear that the difference is due to presence of  $0.75  bars that we intently counted as  $1. \r
\n" ); document.write( "\n" ); document.write( "It is also clear that the number of these  $0.75  bars is  \"20%2F%281.00-0.75%29\" = \"20%2F0.25\" = 80.\r
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\n" ); document.write( "\n" ); document.write( "Thus it gives the answer.\r
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\n" ); document.write( "\n" ); document.write( "For more problems that are solved using this approach see the lessons \r
\n" ); document.write( "\n" ); document.write( "    Problem on animals at a farm     and
\n" ); document.write( "    Problem on pills in containers
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