document.write( "Question 999082: A manufacturer claims that at least 95% of the equipment that she supplied to a
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document.write( "factory confirmed to the specification. An examination of a sample of 200 pieces
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document.write( "of equipment revealed 18 were faulty. Test for her claim at levels of significance (a)
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document.write( "0.01 and (b) 0.05
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Algebra.Com's Answer #616772 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A manufacturer claims that at least 95% of the equipment that she supplied to a \n" ); document.write( "factory conformed to the specification. An examination of a sample of 200 pieces \n" ); document.write( "of equipment revealed 18 were faulty. Test for her claim at levels of significance \n" ); document.write( "(a) 0.01 \n" ); document.write( "Ho: p >= 0.95 (claim) \n" ); document.write( "Ha: p < 0.95 \n" ); document.write( "----- \n" ); document.write( "p-hat = 182/200 = 0.91 \n" ); document.write( "z(0.41) = (0.91-0.95)/sqrt[0.95*0.05/200] = -0.04/sqrt[0.95*0.05/200] \n" ); document.write( "= -2.5955 \n" ); document.write( "-------------- \n" ); document.write( "p-value = P(z < -2.5955) = 0.0047 \n" ); document.write( "------ \n" ); document.write( "Conclusion: Since the p-value is less than 1%, reject Ho ; reject the claim. \n" ); document.write( " \n" ); document.write( "(b) 0.05 \n" ); document.write( "Conclusion:: Since the p-value is less than 5%, reject Ho ; reject the claim. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |