document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999064>Question 999064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of rectangle is 2cm more then twice its breadth . if the perimeter of rectangle 28cm.fins its length and breadth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616762 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call length and breadth, L and B.<BR>\n" );
document.write( "Thus L = 2B + 2<BR>\n" );
document.write( "Also perimeter P = 2L + 2B = 28<BR>\n" );
document.write( "Substitute the first equation into the second and get<BR>\n" );
document.write( "2(2B + 2) + 2B = 28<BR>\n" );
document.write( "4B + 4 + 2B = 28<BR>\n" );
document.write( "6B + 4 = 28<BR>\n" );
document.write( "6B = 24<BR>\n" );
document.write( "B = 4<BR>\n" );
document.write( "L = 10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );