document.write( "Question 999030: Nancy has 4.80 in change. She has three times as many nickels as quaters. She has two more quaters than dimes. How many coins of each does she have? \n" ); document.write( "
Algebra.Com's Answer #616747 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Q=number of quarters \n" ); document.write( "N=number of nickels=3Q \n" ); document.write( "D=number of dimes=Q-2 \n" ); document.write( ". \n" ); document.write( "$0.25Q+$0.05N+$0.10D=$4.80 \n" ); document.write( "$0.25Q+$0.05(3Q)+$0.10(Q-2)=$4.80 \n" ); document.write( "$0.25+$0.15Q+$0.10Q-$0.20=$4.80 \n" ); document.write( "$0.50Q=$5.00 \n" ); document.write( "Q=10 \n" ); document.write( "ANSWER 1: She has 10 quarters. \n" ); document.write( ". \n" ); document.write( "N=3Q=3(10)=30 \n" ); document.write( "ANSWER 2: She has 30 nickels. \n" ); document.write( ". \n" ); document.write( "D=Q-2=10-2=8 \n" ); document.write( "ANSWER 3: She has 8 dimes. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "$0.25Q+$0.05N+$0.10D=$4.80 \n" ); document.write( "$0.25(10)+$0.05(30)+$0.10(8)=$4.80 \n" ); document.write( "$2.50+$1.50+$0.80=$4.80 \n" ); document.write( "$4.80=$4.80 \n" ); document.write( " \n" ); document.write( " |