document.write( "Question 999030: Nancy has 4.80 in change. She has three times as many nickels as quaters. She has two more quaters than dimes. How many coins of each does she have? \n" ); document.write( "
Algebra.Com's Answer #616747 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Q=number of quarters
\n" ); document.write( "N=number of nickels=3Q
\n" ); document.write( "D=number of dimes=Q-2
\n" ); document.write( ".
\n" ); document.write( "$0.25Q+$0.05N+$0.10D=$4.80
\n" ); document.write( "$0.25Q+$0.05(3Q)+$0.10(Q-2)=$4.80
\n" ); document.write( "$0.25+$0.15Q+$0.10Q-$0.20=$4.80
\n" ); document.write( "$0.50Q=$5.00
\n" ); document.write( "Q=10
\n" ); document.write( "ANSWER 1: She has 10 quarters.
\n" ); document.write( ".
\n" ); document.write( "N=3Q=3(10)=30
\n" ); document.write( "ANSWER 2: She has 30 nickels.
\n" ); document.write( ".
\n" ); document.write( "D=Q-2=10-2=8
\n" ); document.write( "ANSWER 3: She has 8 dimes.
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "$0.25Q+$0.05N+$0.10D=$4.80
\n" ); document.write( "$0.25(10)+$0.05(30)+$0.10(8)=$4.80
\n" ); document.write( "$2.50+$1.50+$0.80=$4.80
\n" ); document.write( "$4.80=$4.80
\n" ); document.write( "
\n" ); document.write( "
\n" );