document.write( "Question 999049: The perimeter of a rectangle is 96cm. if the length is double the width, find the length & the width. \n" ); document.write( "
Algebra.Com's Answer #616726 by macston(5194)\"\" \"About 
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\n" ); document.write( "P=perimeter; W=width; L=length=2W
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\n" ); document.write( "P=2(L+W)
\n" ); document.write( "96cm=2(2W+W)
\n" ); document.write( "48cm=3W
\n" ); document.write( "16cm=W
\n" ); document.write( "ANSWER 1: The width is 16 cm.
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\n" ); document.write( "L=2W=2(16cm)=32 cm
\n" ); document.write( "ANSWER 2: The length is 32 cm.
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\n" ); document.write( "CHECK:
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "96 cm = 2(32 cm + 16 cm)
\n" ); document.write( "96 cm = 2(48 cm)
\n" ); document.write( "96 cm = 96 cm
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