document.write( "Question 999041: Suppose that $2600 is initially invested in an account with an APR of 3.3% compounded continuously. \r
\n" ); document.write( "\n" ); document.write( "I created this function, I don't know if it helps:
\n" ); document.write( "f(t)=2600e^(.033t)
\n" ); document.write( "And I calculated that the annual percent change (APY) of the account is 3.36%\r
\n" ); document.write( "\n" ); document.write( "What is the percent change over 10 years for this account?
\n" ); document.write( "Please help!
\n" ); document.write( "Thanks. \n" ); document.write( "
Algebra.Com's Answer #616721 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Suppose that $2600 is initially invested in an account with an APR of 3.3% compounded continuously.
\n" ); document.write( "I created this function, I don't know if it helps:
\n" ); document.write( "f(t)=2600e^(.033t)
\n" ); document.write( "That is correct.
\n" ); document.write( "-------------------------------
\n" ); document.write( "And I calculated that the annual percent change (APY) of the account is 3.36%
\n" ); document.write( "That is correct.
\n" ); document.write( "---------------------------
\n" ); document.write( "
\n" ); document.write( "What is the percent change over 10 years for this account?
\n" ); document.write( "2600e^(0.033*10) = 2600*e^(0.33) = 3616.52
\n" ); document.write( "Percent increase in 10 years:: 1016.52/2600 = 0.391 = 39.1%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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