document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999042>Question 999042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person have some hens and some cows. Number of head is 38 and number of legs 100 then how many cows  and hens  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616718 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Calls hens and cows, x and y.<BR>\n" );
document.write( "Thus x + y = 38<BR>\n" );
document.write( "Now when we count legs, we have<BR>\n" );
document.write( "2x + 4y = 100<BR>\n" );
document.write( "Let's multiply the first equation by two and subtract...<BR>\n" );
document.write( "2x + 4y = 100<BR>\n" );
document.write( "-(2x + 2y = 76)<BR>\n" );
document.write( "which gives<BR>\n" );
document.write( "2y = 24<BR>\n" );
document.write( "y = 12 cows<BR>\n" );
document.write( "x = 26 chickens<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );