document.write( "Question 998930: If (theta) is in the third quadrant and sin(theta)=-(3/5), what is cos(1/2 theta)? Give your answer as a fraction in simplest from.
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Algebra.Com's Answer #616685 by ikleyn(52909)\"\" \"About 
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\n" ); document.write( "1.  First calculate\r
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\n" ); document.write( "\n" ); document.write( "     \"cos%28theta%29\" = \"sqrt%281+-+sin%5E2%28theta%29%29\" = \"sqrt%281+-+%28-3%2F5%29%5E2%29\" = \"sqrt%28%2825-9%29%2F25%29\" = \"sqrt%2816%2F25%29\" = \"-4%2F5\".\r
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\n" ); document.write( "\n" ); document.write( "     The sign is \"minus\" because the angle   \"theta\"   is in the third quadrant.\r
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\n" ); document.write( "\n" ); document.write( "2.  Next,   \"cos%28%281%2F2%29theta%29\" = \"sqrt%28%281+%2B+cos%5E2%28theta%29%29%2F2%29\".\r
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\n" ); document.write( "\n" ); document.write( "     See the lesson  Trigonometric functions of half argument  in this site.\r
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\n" ); document.write( "\n" ); document.write( "     It gives   \"cos%28%281%2F2%29theta%29\" = \"-sqrt%28%281+%2B+cos%5E2%28theta%29%29%2F2%29\" = \"-sqrt%28%281+%2B+%28-4%2F5%29%5E2%29%2F2%29\" = \"-sqrt%28%2825+%2B+16%29%2F%282%2A25%29%29\" = \"-sqrt%2841%2F50%29\".\r
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\n" ); document.write( "\n" ); document.write( "     The sign is  \"minus\"  because the angle   \"alpha%2F2\"   lies in the second quadrant.\r
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