document.write( "Question 998938: Evaluate
\n" ); document.write( "f(x)={2x if x ≤ 0
\n" ); document.write( " {x-2 if x > 0
\n" ); document.write( "at x-0.
\n" ); document.write( "A). f(0)=-2
\n" ); document.write( "B). f(0)=0\r
\n" ); document.write( "\n" ); document.write( "thanks!
\n" ); document.write( "here is a picture of it, if how i typed it doesn't come out right.
\n" ); document.write( "Copy and paste link : http://prntscr.com/8vc6ky
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Algebra.Com's Answer #616680 by fcabanski(1391)\"\" \"About 
You can put this solution on YOUR website!
Look at the function. It shows that when x<=0 f(x) = 2x. So f(0) = 2*0 = 0. \n" ); document.write( "
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