document.write( "Question 998915: you are going on a canoe trip. you go downstream 15 miles in three hours. the trip back to your car takes 5 hours. how fast are you paddling in still water and how fast is the current? \n" ); document.write( "
Algebra.Com's Answer #616667 by mananth(16946)\"\" \"About 
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canoe speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 5 hours
\n" ); document.write( "with current 3 hours
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\n" ); document.write( "Distance against 15 miles distance with 15 miles
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "15 / ( x - y )= 5
\n" ); document.write( "5 ( x - y ) = 15
\n" ); document.write( "5 x - 5 y = 15 ....................1
\n" ); document.write( "
\n" ); document.write( "15 / ( x + y )= 3.00
\n" ); document.write( "3.00 ( x + y ) = 15
\n" ); document.write( "3.00 x + 3.00 y = 15 ...............2
\n" ); document.write( "Multiply (1) by 5
\n" ); document.write( "Multiply (2) by 3
\n" ); document.write( "we get
\n" ); document.write( "25.00 x + -25 y = 75
\n" ); document.write( "9.00 x + 9 y = 45
\n" ); document.write( "34 x = 120
\n" ); document.write( "/ 34
\n" ); document.write( "x = 4 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "5 x -5 y = 15
\n" ); document.write( "18 -5 y = 15
\n" ); document.write( "-5 y = 15 -18
\n" ); document.write( "-5 y = -3 mph
\n" ); document.write( " y = 1
\n" ); document.write( "canoe speed 4 mph
\n" ); document.write( "current speed 1 mph
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