document.write( "Question 998917: Give the slope intercept form of the equation of the line that is perpendicular to 5x+2y=12 and contains the ponint (2,3). \n" ); document.write( "

Algebra.Com's Answer #616666 by mananth(16946) $\"\"$ $\"About$

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5 x + 2 y = 12
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "2 y = -5 x + 12
\n" ); document.write( "Divide by 2
\n" ); document.write( " y = -2 1/ 2 x + 6
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = -2 1/2
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 2/5
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be 2/5
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\n" ); document.write( "m= 2/5 ,point ( 2 , 3 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "3 = 4/ 5 + b
\n" ); document.write( "b= 11/5
\n" ); document.write( "m= 2/5
\n" ); document.write( "The required equation is y = 2/ 5 x + 11/ 5
\n" ); document.write( "m.ananth@hotmail.ca
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