document.write( "Question 998990: Dr. Nick is twice as old as his son. Twenty years ago, he was 4 times as old as his son then. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #616662 by mananth(16946)\"\" \"About 
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let son's age be x
\n" ); document.write( "then father's age = 2x\r
\n" ); document.write( "\n" ); document.write( "20 years ago their ages\r
\n" ); document.write( "\n" ); document.write( "son (x-20)
\n" ); document.write( "father ---- (2x-20)\r
\n" ); document.write( "\n" ); document.write( "According to the information\r
\n" ); document.write( "\n" ); document.write( "(2x-20)=4(x-20)\r
\n" ); document.write( "\n" ); document.write( "2x-20 = 4x-80\r
\n" ); document.write( "\n" ); document.write( "2x=60\r
\n" ); document.write( "\n" ); document.write( "/2
\n" ); document.write( "x=30\r
\n" ); document.write( "\n" ); document.write( "Son's age = 30\r
\n" ); document.write( "\n" ); document.write( "Father's age = 30*2 = 60\r
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