document.write( "Question 998974: assume the random variable X is normally distributed with mean u=50 and standard deviation o=7. find the 96th percentile \n" ); document.write( "
Algebra.Com's Answer #616640 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z(0.96)=+1.751 \n" ); document.write( "That is the number of standard deviations from the mean \n" ); document.write( "12.257 units from the mean, or 62.257 is the 96th percentile. \n" ); document.write( " |