document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998912>Question 998912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me because I have done this problem over and over. I have never been good at math. Please show all steps. Thanks\r<BR>\n" );
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document.write( "3. For a student recreation building at Northland Community College, an architect wants to lay out a rectangular piece of land that has a perimeter of 204m and an area of 2565m^2. Find the dimensions of the land (Hint: write a system of two equations, then solve the system.) <BR>\n" );
document.write( " After I did it my answer I came up with was 125m^2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616624 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "L = length of rectangle<BR>\n" );
document.write( "W = width of rectangle<BR>\n" );
document.write( "A = area of rectangle<BR>\n" );
document.write( "P = perimeter of rectangle\r<BR>\n" );
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document.write( "A = L*W<BR>\n" );
document.write( "P = 2*(L+W)\r<BR>\n" );
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document.write( "\"perimeter of 204m\" ---> P = 204<BR>\n" );
document.write( "\"area of 2565m^2\" ----> A = 2565\r<BR>\n" );
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document.write( "P = 2*(L+W)<BR>\n" );
document.write( "204 = 2*(L+W) ... plug in P = 204<BR>\n" );
document.write( "204/2 = 2*(L+W)/2 ... Divide both sides by 2.<BR>\n" );
document.write( "102 = L+W<BR>\n" );
document.write( "L+W = 102<BR>\n" );
document.write( "L+W-W = 102-W ... Subtract W from both sides.<BR>\n" );
document.write( "L = 102-W\r<BR>\n" );
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document.write( "A = L*W<BR>\n" );
document.write( "2565 = L*W ... plug in A = 2565<BR>\n" );
document.write( "2565 = (102-W)*W ... replace L with 102-W<BR>\n" );
document.write( "2565 = W*(102-W)<BR>\n" );
document.write( "2565 = W*102+W*(-W)<BR>\n" );
document.write( "2565 = 102W-W^2<BR>\n" );
document.write( "2565-2565 = 102W-W^2-2565 ... Subtract 2565 from both sides.<BR>\n" );
document.write( "0 = 102W-W^2-2565<BR>\n" );
document.write( "-W^2+102W-2565 = 0\r<BR>\n" );
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document.write( "Use the quadratic formula to solve the last equation above to get W = 45 or W = 57\r<BR>\n" );
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document.write( "If W = 45, then<BR>\n" );
document.write( "L = 102-W<BR>\n" );
document.write( "L = 102-45<BR>\n" );
document.write( "L = 57\r<BR>\n" );
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document.write( "If W = 57, then<BR>\n" );
document.write( "L = 102-W<BR>\n" );
document.write( "L = 102-57<BR>\n" );
document.write( "L = 45\r<BR>\n" );
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document.write( "So we see that the dimensions of this rectangle are <font color=\"red\">57 meters by 45 meters</font> </SPAN>\n" );
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