document.write( "Question 998846: On an upstream trip, a canoe travels 40 km in 5 hours. Downstream, it travels the same distance in half the time. What is the rate of the canoe in still water and the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #616604 by ikleyn(52814)\"\" \"About 
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\n" ); document.write( "On an upstream trip, a canoe travels 40 km in 5 hours. Downstream, it travels the same distance in half the time.
\n" ); document.write( "What is the rate of the canoe in still water and the rate of the current?
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\n" ); document.write( "\n" ); document.write( "On an upstream trip,  the canoe speed relative to the river banks is  \"40_km%2F5_hours\" = 8 \"km%2Fh\". \r
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\n" ); document.write( "\n" ); document.write( "This speed is the difference of the speed of canoe relative water,  u,  and the speed of current,  v:\r
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\n" ); document.write( "\n" ); document.write( "8 = u - v.         (1)\r
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\n" ); document.write( "\n" ); document.write( "Downstream,  the canoe speed relative to the river banks is twice more:  \"40%2F2.5\" = 16 \"km%2Fh\".\r
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\n" ); document.write( "\n" ); document.write( "This speed is the sum of the speed of canoe relative water,  u,  and the speed of current,  v:\r
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\n" ); document.write( "\n" ); document.write( "16 = u + v.         (2)\r
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\n" ); document.write( "\n" ); document.write( "Add  (1)  and  (2).  You will get \r
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\n" ); document.write( "\n" ); document.write( "2u = 8 + 16 = 24,  hence,  u = \"24%2F2\" = 12 \"km%2Fh\".\r
\n" ); document.write( "\n" ); document.write( "Then  v = 4 \"km%2Fh\".\r
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\n" ); document.write( "\n" ); document.write( "Answer.  The canoe speed in a still water is  12 \"km%2Fh\". \r
\n" ); document.write( "\n" ); document.write( "              The current speed is  4 \"km%2Fh\".\r
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