document.write( "Question 998824: The given equations are quadratic. Solve analytically.
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document.write( "a) 3^2x + 35 = 12(3^x)
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document.write( " 3^2x-36^x + 35 = 0
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document.write( " (3^x-35)(l^x-1)=0
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document.write( "not sure if I started this correctly or not. \r
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document.write( "b) I was not sure how to do this one
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document.write( " 2(lnx)^2 + 9 lnx =5
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Algebra.Com's Answer #616572 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a) 3^2x + 35 = 12(3^x) \n" ); document.write( "(3^x)^2-36*3^x + 35 = 0 \n" ); document.write( "(3^x-35)(3^x-1)=0 \n" ); document.write( "3^x = 35 of 3^x = 1 \n" ); document.write( "---- \n" ); document.write( "x = log(35)/log(3) or x = log(1)/log(3) \n" ); document.write( "x = 1.8654 or x = 0 \n" ); document.write( "-------------------------- \n" ); document.write( "b) I was not sure how to do this one \n" ); document.write( "2(lnx)^2 + 9 lnx - 5 = 0 \n" ); document.write( "(2ln(x)-1)(2ln(x)+5) = 0 \n" ); document.write( "---- \n" ); document.write( "ln(x) = 1/2 or ln(x) = -5/2 \n" ); document.write( "------ \n" ); document.write( "x = e^(1/2) or x = e^(-5/2) \n" ); document.write( "------------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |