document.write( "Question 998790: two biased coins with probability of head is 0.3 on coin one and probability of head is 0.4 on coin two are tossed simultaneously. find probability of
\n" ); document.write( "A.two heads
\n" ); document.write( "B.coin one shows head
\n" ); document.write( "C.one head
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Algebra.Com's Answer #616571 by mathmate(429)\"\" \"About 
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\n" ); document.write( "Problem:
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\n" ); document.write( "Two biased coins are tossed simultaneously.
\n" ); document.write( "Coin A has probability of 0.3 for heads, and
\n" ); document.write( "coin B has probability of 0.4 for heads.
\n" ); document.write( "Find
\n" ); document.write( "(a) two heads
\n" ); document.write( "(b) coin A shows head
\n" ); document.write( "(c) one head
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\n" ); document.write( "Solution:
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\n" ); document.write( "Define event Ha=coin A shows heads, Hb=coin B shows heads.
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\n" ); document.write( "(a) Two heads
\n" ); document.write( "The two coins are independent of each other, so probability of both events (heads) happening is the product of the individual probabilities.
\n" ); document.write( "Probability of two heads
\n" ); document.write( "= P(Ha and Hb)
\n" ); document.write( "= P(Ha)*P(Hb)
\n" ); document.write( "= 0.3*0.4
\n" ); document.write( "= 0.12
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\n" ); document.write( "(b) Coin A shows head
\n" ); document.write( "This means that the outcome of coin B is immaterial, so
\n" ); document.write( "P(Ha)=0.3
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\n" ); document.write( "(c) one head
\n" ); document.write( "This means exactly one head, which is either
\n" ); document.write( "event Ha and ~Hb
\n" ); document.write( "or
\n" ); document.write( "event ~Ha and Hb.
\n" ); document.write( "The two events are independent and mutually exclusive, so we can add the two probabilities.
\n" ); document.write( "P(Ha and ~Hb)=0.3*(1-0.4)=0.18
\n" ); document.write( "P(~Ha and Hb)=(1-0.3)*0.4=0.28
\n" ); document.write( "Probability of showing exactly one head
\n" ); document.write( "= 0.18+0.28
\n" ); document.write( "= 0.46
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