document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998811>Question 998811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the age of father exceeds to the square of the age of his son by 4 years. the sum of the age of father and four times the age of his son is 64 years. find their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616563 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let son be y years<BR>\n" );
document.write( "father be x years\r<BR>\n" );
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document.write( "x= y^2+4\r<BR>\n" );
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document.write( "x+4y =64\r<BR>\n" );
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document.write( "substitute x\r<BR>\n" );
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document.write( "y^2+4+4y=64\r<BR>\n" );
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document.write( "y^2+4y-60=0\r<BR>\n" );
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document.write( "y^2+10y-6y+60=0\r<BR>\n" );
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document.write( "y(y+10)-6(y+10)=0\r<BR>\n" );
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document.write( "(y+10)(y-6)=0\r<BR>\n" );
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document.write( "y= 6 OR -10\r<BR>\n" );
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document.write( "discard -10\r<BR>\n" );
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document.write( "son's age = 6 years\r<BR>\n" );
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document.write( "Father's age = 40 years\r<BR>\n" );
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document.write( " </SPAN>\n" );
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