document.write( "Question 998759: 8.32 In a survey of 2,395 adults, 1,916 reported that
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document.write( "e-mails are easy to misinterpret, but only 1,269 reported that
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document.write( "telephone conversations are easy to misinterpret. (Data
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document.write( "extracted from “Open to Misinterpretation,” USA Today,
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document.write( "July 17, 2007, p. 1D.)
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document.write( "a. Construct a 95% confidence interval estimate for the
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document.write( "population proportion of adults who report that e-mails
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document.write( "are easy to misinterpret.
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document.write( "b. Construct a 95% confidence interval estimate for the
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document.write( "population proportion of adults who report that telephone
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document.write( "conversations are easy to misinterpret.
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document.write( "c. Compare the results of (a) and (b).\r
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document.write( "8.40 If a quality control manager wants to estimate, with
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document.write( "95% confidence, the mean life of light bulbs to within +- 20 hours and also assumes that the population standard
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document.write( "deviation is 100 hours, how many light bulbs need to be
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document.write( "selected? \n" );
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Algebra.Com's Answer #616507 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The proportion in the sample was 0.8 \n" ); document.write( "The SE is sqrt ((0.8)(0.2/2395}=0.00817 \n" ); document.write( "a 95% CI is 1.96*SE for the interval half width. \n" ); document.write( "It equals 0.016 \n" ); document.write( "The CI is (0.784,0.816) \n" ); document.write( "===== \n" ); document.write( "Telephone \n" ); document.write( "0.5298 is point estimate proportion \n" ); document.write( "SE={0.5298*0.4702/2395}^(1/2)=0.0102 \n" ); document.write( "1.96*SE=0.02 \n" ); document.write( "The CI is (0.51,0.53). More decimal places may be added if desired. The CI is wider, because the proportion is closer to 0.5 \n" ); document.write( "========= \n" ); document.write( "sample size unknown \n" ); document.write( "we know that 1.96 * SE is the interval, and the interval must be +/- 20 hours \n" ); document.write( "The SE is the SD/sqrt(n) \n" ); document.write( "1.96*SD/sqrt(n)=20 \n" ); document.write( "square both sides \n" ); document.write( "3.84*10000/n =400 \n" ); document.write( "n=38416/400=96.04 round to 97 \n" ); document.write( "Check this \n" ); document.write( "mean +/- s/sqrt(n) \n" ); document.write( "that is 100/sqrt(97)=10.153 \n" ); document.write( "That *1.96=19.90, slightly below 20 because need to round the 96.04 up to next higher. \n" ); document.write( "97 light bulbs. \n" ); document.write( " \n" ); document.write( " |