document.write( "Question 998738: steve travels 4 times as fast as fred. traveling in opposite directions, they are 105 miles apart after 3 hours. find their rates of travel. \n" ); document.write( "
Algebra.Com's Answer #616500 by stanbon(75887)\"\" \"About 
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steve travels 4 times as fast as fred. traveling in opposite directions, they are 105 miles apart after 3 hours. find their rates of travel.
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\n" ); document.write( "Steve DATA\"
\n" ); document.write( "rate 4x ; time = 3 hrs ; distance = 3*4x = 12x miles
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\n" ); document.write( "Fred DATA:
\n" ); document.write( "rate = x ; time = 3 hrs ; distance 3x miles
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\n" ); document.write( "Equation:
\n" ); document.write( "dist + dist = 105 miles
\n" ); document.write( "12x + 3x = 105
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\n" ); document.write( "15x = 105
\n" ); document.write( "x = 7 mph (Fred's rate)
\n" ); document.write( "4x = 28 mph (Steve's rate)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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