document.write( "Question 998738: steve travels 4 times as fast as fred. traveling in opposite directions, they are 105 miles apart after 3 hours. find their rates of travel. \n" ); document.write( "
Algebra.Com's Answer #616500 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! steve travels 4 times as fast as fred. traveling in opposite directions, they are 105 miles apart after 3 hours. find their rates of travel. \n" ); document.write( "========= \n" ); document.write( "Steve DATA\" \n" ); document.write( "rate 4x ; time = 3 hrs ; distance = 3*4x = 12x miles \n" ); document.write( "------ \n" ); document.write( "Fred DATA: \n" ); document.write( "rate = x ; time = 3 hrs ; distance 3x miles \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "dist + dist = 105 miles \n" ); document.write( "12x + 3x = 105 \n" ); document.write( "----- \n" ); document.write( "15x = 105 \n" ); document.write( "x = 7 mph (Fred's rate) \n" ); document.write( "4x = 28 mph (Steve's rate) \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |